考虑到树状数组是一颗树,然后染色的做法
#include <bits/stdc++.h>
/*
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/hash_policy.hpp>
*/
using namespace std;
const double eps = 1e-10;
const double pi = 3.1415926535897932384626433832795;
const double eln = 2.718281828459045235360287471352;
#define f(i, a, b) for (int i = a; i <= b; i++)
#define scan(x) scanf("%d", &x)
#define mp make_pair
#define pb push_back
#define lowbit(x) (x&(-x))
#define fi first
#define se second
#define SZ(x) int((x).size())
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define summ(a) (accumulate(all(a), 0ll))
typedef unsigned long long ull;
typedef pair<int,int> pii;
typedef vector<int> vi;
using ll=long long;
int tt,n,a[(int)1e5+9],ans,cn[(int)1e5+9];
char c;
vi g[(int)1e5+9];
void dfs(int x){
a[x]=0;
bool ok=1;
for(auto it:g[x]){
if(a[it]){
dfs(it);
ok=0;
}
}
ans+=ok;
}
int main()
{
for(int i=1;i<=1e5;++i){
int tmp=i+lowbit(i);
if(tmp<=1e5)g[tmp].push_back(i);
}
scanf("%d",&tt);
f(sb,1,tt){
ans=0;
scanf("%d",&n);
for(int i=1;i<=n;++i)scanf(" %c",&c),a[i]=c=='1',cn[i]=0;
for(int i=n;i;--i){
if(a[i]){
dfs(i);
int tmp=i+lowbit(i);
if(tmp<=n)cn[tmp]+=1;
}
}
for(int i=1;i<=n;++i)ans+=cn[i]==1;
printf("%d\n",ans);
}
return 0;
}